how get filename from line number.

[drjs5x]

hi dears
how get filename from line number. example line 157 file= test.avi
get(filename(#157)) ; how can get filename from line number??
or full path ... c:\test55444\test.avi
...
thanks

[highend]

E.g.

Code: Select all

    $line = 157;

    $path = gettoken(listpane(), $line, "|");
    $base = gpc($path, "file");

[drjs5x]

very good fine working.